Created almost 9 years ago, updated 5 months ago
ID 23538
A− A+
Example: Row-reduce and identify pivot columns:
$$A = \begin{pmatrix} 1 & 3 & 2 & 1 \\ 2 & 6 & 5 & 4 \\ 1 & 3 & 1 & 2 \end{pmatrix}$$
Row reduction:
$R_2 \leftarrow R_2 - 2R_1$, $R_3 \leftarrow R_3 - R_1$:
$$\begin{pmatrix} 1 & 3 & 2 & 1 \\ 0 & 0 & 1 & 2 \\ 0 & 0 & -1 & 1 \end{pmatrix}$$
$R_3 \leftarrow R_3 + R_2$:
$$\begin{pmatrix} 1 & 3 & 2 & 1 \\ 0 & 0 & 1 & 2 \\ 0 & 0 & 0 & 3 \end{pmatrix}$$
Pivot columns: Columns 1, 3, and 4 (positions of leading entries in the echelon form). Column 2 is not a pivot column — it corresponds to a free variable.
**Example:** Row-reduce and identify pivot columns:
$$A = \begin{pmatrix} 1 & 3 & 2 & 1 \\ 2 & 6 & 5 & 4 \\ 1 & 3 & 1 & 2 \end{pmatrix}$$
**Row reduction:**
1. $R_2 \leftarrow R_2 - 2R_1$, $R_3 \leftarrow R_3 - R_1$:
$$\begin{pmatrix} 1 & 3 & 2 & 1 \\ 0 & 0 & 1 & 2 \\ 0 & 0 & -1 & 1 \end{pmatrix}$$
2. $R_3 \leftarrow R_3 + R_2$:
$$\begin{pmatrix} 1 & 3 & 2 & 1 \\ 0 & 0 & 1 & 2 \\ 0 & 0 & 0 & 3 \end{pmatrix}$$
**Pivot columns:** Columns 1, 3, and 4 (positions of leading entries in the echelon form). Column 2 is not a pivot column — it corresponds to a free variable.Copy