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Equivalence theorem for nonsingular matrices: the linear transformation given by T(x)=Ax is onto/surjective.

Created over 8 years ago, updated 10 days ago

Theorem: An $n \times n$ matrix $A$ is nonsingular iff $T(x) = Ax$ is onto (surjective). $T$ is surjective iff the column space of $A$ is all of $\mathbb{R}^n$, i.e., $\text{rank}(A) = n$.