Dashboard

Featured nodes

Roots

  • Public root

Templates

  • Test template
  • iCorps template
  • Guanyu's Latex template
  • Ivar's latex template
  • Family Tree template
  • Latex template
  • Router template

Trees

  • Public trees

Orphans

  • Browse orphan nodes
Related nodes

Parents1

  • Using matrices to solve linear systems

Siblings2
  • Sort by title
  • Sort by date

  • Example of solving a 3-by-3 system of linear equations by row-reducing the augmented matrix
  • Example of solving a 3-by-3 homogeneous system of linear equations by row-reducing the augmented matrix
Knowenβ
  • Help
    • Welcome to Knowen!
    • Edit test node (no login required)
    • Create new test node (no login required)
  • Not logged in
    • Sign in
    • Sign up

History & Comments

Back

Fill content

Description:Added 3x3 homogeneous system solving example
# Example of solving a 3-by-3 homogeneous system of linear equations by row-reducing the augmented matrix

Put content here## Example: Solving a 3-by-3 Homogeneous System by Row Reduction
⏎
Solve the homogeneous system:
```
 x + 2y + 3z = 0
2x + 5y + 3z = 0
 x + 8z = 0
```
⏎
**Step 1:** Write augmented matrix (right column is always 0 for homogeneous systems)
```
[ 1  2  3 | 0]
[ 2  5  3 | 0]
[ 1  0  8 | 0]
```
⏎
**Step 2:** R₂ → R₂ - 2R₁, R₃ → R₃ - R₁
```
[ 1  2  3 | 0]
[ 0  1 -3 | 0]
[ 0 -2  5 | 0]
```
⏎
**Step 3:** R₃ → R₃ + 2R₂
```
[ 1  2  3 | 0]
[ 0  1 -3 | 0]
[ 0  0 -1 | 0]
```
⏎
**Step 4:** R₃ → -R₃
```
[ 1  2  3 | 0]
[ 0  1 -3 | 0]
[ 0  0  1 | 0]
```
⏎
**Step 5:** Back-substitute: z = 0, y = 3(0) = 0, x = -2(0) - 3(0) = 0
⏎
**Solution:** The only solution is the trivial solution x = 0, y = 0, z = 0.
⏎
This homogeneous system has only the trivial solution because the coefficient matrix has full rank (3 pivots). When a homogeneous system has free variables, nontrivial solutions exist.

# Parents

* Using matrices to solve linear systems
* Using matrices to solve linear systems
Sign in to add a new comment

Contact us or leave feedback

© KTree Inc. 2026